Question

two forces , each of magnitude p are inclined at 60° find the magnitude and direction of their difference???​

Answer 1

Let the forces = A vector

we know

resultant vector = √asquared + bsquared - 2abcostheta ( since it is difference )

here a=b

so magnitude of resultant = √ a^2 + a^2 - 2a^2cos60

cos60 = 1/2


so magnitude of resultant = √ a^2 + a^2 - 2 x 1/2x a^2

solving we get √a^2
resultant vector ==> a //


for direction ,

tan α = bsinθ/ a+ bcosθ
= ( a√3/2) / a -a/2
= a√3/2
—————
a/2.

=. 2√3 / 2 ===> √3