Two forces equal to f and 3f newton act on a particle .if the first force be triplled and the second force be increased by 30 newton .the direction of the resultant is unltered .find the value of f
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Let the resultant make angle x with the force f
So, in first case
tan x = 3f sin Ф / (f + 3f cos Ф)
In second case,
tan x = [ (3f + 30) sin Ф ] / [ 3f + (3f + 30) cos Ф ]
So
3f sin Ф / (f + 3f cos Ф) = [ (3f + 30) sin Ф ] / [ 3f + (3f + 30) cos Ф ]
3f sin Ф / (f + 3f cos Ф) = 30 sin Ф / f + 30 cos Ф
[as a/b = c/d = (a-c)/(b-d) ]
So, from above equation,
3f = 30
f = 10 N
So, in first case
tan x = 3f sin Ф / (f + 3f cos Ф)
In second case,
tan x = [ (3f + 30) sin Ф ] / [ 3f + (3f + 30) cos Ф ]
So
3f sin Ф / (f + 3f cos Ф) = [ (3f + 30) sin Ф ] / [ 3f + (3f + 30) cos Ф ]
3f sin Ф / (f + 3f cos Ф) = 30 sin Ф / f + 30 cos Ф
[as a/b = c/d = (a-c)/(b-d) ]
So, from above equation,
3f = 30
f = 10 N
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