Question

Two forces F1 and F2 are acting on a body. Find the magnitude and direction of

a third force F which must be applied on the body in order to bring it to

equilibrium in the following cases.

I. F1 = (i+2j-k)N and F2 = (2i-j-k)N.​

Answer 1

Explanation:

ANSWER

Given that,

Two forces F

1

and F

2

=5N

Angle θ=60

0

We know that, the resultant force is

∣F∣=∣F

1

∣+∣F

2

∣

∣F∣=

F

1

2

+F

2

2

+2F

1

F

2

cosθ

∣F∣=

(5)

2

+(5)

2

+2×5×5×

2

1

∣F∣=

75

∣F∣=8.66N

Hence, the resultant force acting on the body is 8.66 N

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Answer 2

Answer:

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