Question

Two forces F1 = (i+j) N and F2 = { 3/2j + 2k) N are acting on a block. The component of force 1,
perpendicular to force 7,, is
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Answer 1

Answer:

Two forces F1 and F2 =5N. Angle θ=600. We know that, the resultant force is. ∣F∣=∣F1∣+∣F2∣. ∣F∣=F12+F22+2F1F2cosθ . ∣F∣=(5)2+(5)2+2×5×5×21 . ∣F∣=75