Two forces is equal to P and 2P respectively at on the particle . when the first process increase by on different and the 2nd force double . the direction and resultant will same Determine the value of P
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From the given parameters,
F1net = root(P2 + 4p2 + 4p2) = underroot(9p2)
F2net = underroot(4p2 + (2p + 20)2 + 4p.(2p+20)) = underroot(16p2 + 160p +400)
Both the forces would be equal as given,
Hence, F1net = F2net
7p2 +160p +400 = 0
p = - 40/28 = -10/7 N
and also
p = - 100 N
These would be the forces acting in oppsote direction........m
F1net = root(P2 + 4p2 + 4p2) = underroot(9p2)
F2net = underroot(4p2 + (2p + 20)2 + 4p.(2p+20)) = underroot(16p2 + 160p +400)
Both the forces would be equal as given,
Hence, F1net = F2net
7p2 +160p +400 = 0
p = - 40/28 = -10/7 N
and also
p = - 100 N
These would be the forces acting in oppsote direction........m
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