Two forces of 10N and 18N act on a particle and their line of action are inclined at an angle 150°.Find the third force which must be applied upon the particle to keep it in equilibrium?
Answers
Answered by
1
Explanation:
resolve the forces along x and y axes
net force along both axes must be zero
present net force is (10-9√3)i+9j
3rd force must be -((10-9√3)i+9j)
its magnitude=10.6N
Attachments:
Similar questions