Two forces of 10n and 6n act upon a body. the direction of forces are unkown. the resultant forces on the body may be...
1. 15n
2. 3n
3.17n
4. 2n
pls answer step wise n reason for considering theta=??...
pls
Answers
Answer:
Correct option
1.) 15 N
Explanation:
given that,
Two forces of 10n and 6n act upon a body.
and also given that,
the direction is unknown so,
ф between the forces also not given,
let the forces be A and B
where,
A = 10 N
B = 6 N
Resultant of the two forces
= √(A² + B² + 2AB cosф)
putting the values,
Resultant force
= √(10² + 6² + 2(10)(6)cosф)
= √(100 + 36 + 120cosф)
= √(136 + 120cosф)
now,
maximum value of cosф = 1
where
ф = 0°
now,
putting the value of ф as 0°
Resultant = √(136 + 120cosф)
= √(136 + 120 × cos0°)
= √(136 + 120 × 1)
= √(136 + 120)
= √256
= 16 N
and
minimum value of cosф = -1
where,
ф = 180°
so,
Resultant = √(136 + 120cos180)
= √(136 + 120 × (-1))
= √(136 - 120)
= √16
= 4 N
now here,
Maximum resultant = 16 N
Minimum resultant = 4 N
now,
in the options,
1.) 15 N
is between the maximum and minimum resultant force
so,