Two forces of 12 and and 8 n act upon a body find the maximum and minimum resultant
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Hey.
Here is the answer.
As resultant R is given by
R = √( a^2 +b^2 +2ab cosx)
where a and b are two vectors inclined at an angle x °.
So, for maximum:
cosx = 1
so, Rmax = √(12^2+8^2+2×12×8)
= √(144+64+192)
=√400
= 20 N
For minimum;
cosx = -1
So, Rmin = √(12^2+8^2-2×12×8)
=√(144+64-192)
=√16
= 4 N
Thanks.
Here is the answer.
As resultant R is given by
R = √( a^2 +b^2 +2ab cosx)
where a and b are two vectors inclined at an angle x °.
So, for maximum:
cosx = 1
so, Rmax = √(12^2+8^2+2×12×8)
= √(144+64+192)
=√400
= 20 N
For minimum;
cosx = -1
So, Rmin = √(12^2+8^2-2×12×8)
=√(144+64-192)
=√16
= 4 N
Thanks.
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