Question

two forces of 20 N each act vertically upward and downward respectively on two ends of uniform rod length 1 m pivoted freely at its centre . Determine the resultant moment of force about the midpoint of rod​

Answer 1

Answer:

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Explanation:

moment of force=amount of force×perpendicular distance..

so mof=20N×1m

=20Nm(answer)

Answer 2

Answer:

Explanation:

half of 1m = 0.5m

Torque at point A = 20×0.5 = 10Nm

Torque at point B = 20×0.5 = 10Nm

Torque1 + Torque2

= 10 + 10

= 20Nm Ans.

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