Question

Two Forces of 200N and 120N are inclined at an angle of 60°. The resultant force will be

Answer 1

Given :

F1 = 200 N

F2 = 120 N

Φ = 60

we know that ,

the resultant force is

$\sqrt{ {f1}^{2} + {f2}^{2} \ + 2f1f2 \cos( \alpha ) }$

therefore,


F (resultant) =
$\sqrt{ {200}^{2} + {120}^{2} + 2 \times 200 \times 120 \times \frac{1}{2} }$

therefore,

F (resultant) =

√ 40000 + 14400 + 24000

√78400

therefore,

F(resultant) = 280 N

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