Question

Two forces of 4dyne and 3dyne act upon a body. The resultant force on the body can only be​

Answer 1

Answer:

Resultant force will be between 1 dyne to 7 dyne.

Explanation:

Resultant force F of two force P and Q acting on a body and angle between force P and Q is β

$F = \sqrt{P^{2} + Q^{2} + 2PQcos\beta }$

value of β for minimum Force is 180° and for maximum force is 0°.

$F_{min}= \sqrt{4^{2} + 3^{2} + 2*4*3cos180 }$ = 1dyne

$F_{max}= \sqrt{4^{2} + 3^{2} + 2*4*3cos0 }$ = 7dyne

So Resultant force will be between 1 dyne to 7 dyne.