two forces of 4n acts on a body at an angle of 60 degree find magnitude and direction of the resultant force acting on the body
Answers
Answered by
8
Magnitude of resultant force = 6.93 N
Direction = 30° between the two forces
Explanation:
Two forces of 4 N.
Angle θ = 60°
Resultant force = √ (a² + b² + 2abCos θ)
= √ 4² + 4² + 2(4)(4).Cos60°
= √ 16 + 16 + 32 (1/2)
= √ 32 + 16
= √48
= 6.93 N
Direction: Since both the forces are equal and 60° from each other, the resultant force will be at 30° between them.
Answered by
5
Answer:
Magnitude of resultant force = 6.93 N
Direction = 30° between the two forces
Explanation:
Two forces of 4 N.
Angle θ = 60°
Resultant force = √ (a² + b² + 2abCos θ)
= √ 4² + 4² + 2(4)(4).Cos60°
= √ 16 + 16 + 32 (1/2)
= √ 32 + 16
= √48
= 6.93 N
Direction: Since both the forces are equal and 60° from each other, the resultant force will be at 30° between them.
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