Question

Two forces of 5 N and 10 N acting at a point have an angle of 120° between them. Find
the magnitude and direction of the resultant force. [8.66 N; 30° with 10 N force]
Two equal forces F have a resultant of 15 F Find then​

Answer 1

Explanation:

Here suppose P=5N and Q=10N and angle=120*

the magnitude of resultant=r  then,

r^{2}=P^{2}+Q^{2}+2*cos120

r^{2}=5^{2}+10^{2}+2*1/2

on solving we get

resultant=\sqrt{25+100}

resultant=11.2N

for  direction use

tan\beta=(Qsin120)/P+Qcos120