Two forces of 5 N and 10 N acting at a point have an angle of 120° between them. Find the magnitude and direction of the resultant resistant.
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R = √A2 + B2 +2AB CosQ(theta)
R = √5^2 + 10^2 +2×10×5 Cos 120°
R = √25+100+50
R = 5√7
Direction :
tanQ = BSinQ/A + B sinQ
tanQ = 5√3/2 ×. 2/15
tanQ = √3/3
tanQ = 1/√3
TanQ = 30°
R = √5^2 + 10^2 +2×10×5 Cos 120°
R = √25+100+50
R = 5√7
Direction :
tanQ = BSinQ/A + B sinQ
tanQ = 5√3/2 ×. 2/15
tanQ = √3/3
tanQ = 1/√3
TanQ = 30°
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