Two Forces of 5N and 10 N are acting on a body with an inclination of 120° between them , find the magnitude and direction of resultant force wrt the 10N force?
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Answer:
5√3, 30°
Explanation:
Let P be the force of 5 kg weight and Q be the force of 10 kg weight.
By parallelogram law of vector addition, the resultant is,
R²=P² + Q² + 2PQcos120° = 25 + 100 + 2*5*10 cos 120°
R = 5√3
Let α be the angle made by R with 10 kg weight.
tan α = P sinФ/(P + QcosФ)
tan α = 1/√3 = tan 30°
α = 30°
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