Question

Two forces of 5N and 7N on a particle with an angle 60 degree between them find resultant R.​

Answer 1

▶ Question:-

→ Two forces of 5N and 7N acts on Na particle with an angle 60 degree between them. Find resultant force ( R ) .​

▶Answer :-

→ R = √(109) N .

▶ Step-by-step explanation :-

➡ Given :-

→ $\sf F_1 = 5 N$ .

→ $\sf F_2 = 7 N$ .

→ $\sf \theta = 60 \degree$ .

➡ To Find :-

→ The resultant force ( R ) .

$\huge \pink{ \mid \underline{ \overline{ \sf Solution :- }} \mid}$

▶ Now,

Using Identity :-

$\because \sf Resultant \: force = \sqrt{ {F_1}^{2} + {F_2}^{2} + 2F_1F_2 \cos \theta}. \\ \\ \sf = \sqrt{ {5}^{2} + {7}^{2} + 2 \times 5 \times 7 \times \cos60 \degree} . \\ \\ \sf = \sqrt{25 + 49 + 70 \times \frac{1}{2} } . \: \: \bigg( \therefore\cos60 \degree = \frac{1}{2} \bigg) \\ \\ \sf = \sqrt{25 + 49 + 35} . \\ \\ \huge \boxed{ \green{ \sf = \sqrt{109} \: N.}}$

✔✔ Hence, it is solved ✅✅.

THANKS

Answer 2

Answer:

Answer is given above.