Question

Two forces of a N acts on a
body at an angle
of 60'. find
. magnitude and direction of
the resultant force acting on the body.​

Answer 1

Answer:

fcostheta = 2

fsintheta = 2√3

As fsintheta is more the force is in direction of fsinththeta

Answer 2

Answer:

$\sqrt{x {}^{2} + y {}^{2} + 2xy \cos( \alpha ) }$

alpha is angle so acc to this resultant is N root 2+√3

√3=1.732

ans -: N √3.732