Question

two forces of magnitude 10N and 20N act on a body in directions making angle of 30° with z-axis,the x-component of the resultant force will be:
a.25.98N
b.3.98N
c.20.98N
d.17.98N​

Answer 1

Answer:

This cannot be answered with the given information. Are the y components of both forces positive or negative, or one of each. If the latter, which one is positive. Thus there are four answers. I presume you mean that the angles are measured from the positive direction of the x axis, otherwise there will be eight answers.

The x components of the forces are  103√2N  and  10N . The y components are  ±5  and  ±203√2N .

So the x component of the resultant is  (53–√+10)N , and the y component is  (±5+±103–√)N . Decide on the signs and you will have an answer.

Answer 2

Answer:

The resultant force is 29 N.

Explanation:

EXPLANATION:

The resultant of two forces are determined by the parallelogram rule as follows:

As the forces acting at different angle, so the resultant force will have magnitude related to the difference in the angle in which the incident forces were acted.

\text { Resultant }=\sqrt{F_{1}^{2}+F_{2}^{2}+2 F_{1} F_{2} \cos \left(\theta_{2}-\theta_{1}\right)}

Here F1 and F2 are the two forces acting and their respective angles are given as and

So the resultant force will be

\text { Resultant force }=\sqrt{(10)^{2}+(20)^{2}+2 *(10 * 20) \cos (60-30)}

\text { Resultant force }=\sqrt{100+400+400 \cos (30)}

\text { Resultant force }=\sqrt{500+\left(400 * \frac{\sqrt{3}}{2}\right)}

\text { Resultant force }=\sqrt{500+(200 * 1.732)}

\text { Resultant force }=\sqrt{846.4}

Thus, the resultant force is 29 N.