Two forces of magnitude 10N each add to produce a resultant of 10V3N. Find the angle between the
two forces.
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R square is equals to a square + b square + 2 a b cos theta where R is resultant and A and B are the two forces having a magnitude of 10 Newton so so using this formula
R^2= a^2+b^2+2abcostheta
here r is 10 underroot 3 so,
(10 underroot3)^2 =10^2 + 10^2 +2×10×10Cos thetea
300=100+100+200cos theta
300= 200+200cos theta
300=200( 1+cos theta)
300/200=1+cos theta
3/2 - 1 = cos theta
1/2 = cos theta
theta = 60 degrees
because at 60 dehrees the value of cos theta is 1/2
so,,
《ANGLE = 60°》
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