Question

Two Forces Of Magnitude 20N Each Are Acting At 30 And 60 degree with xAxis the Y Component Of The Resultant Force Is​

Answer 1

Answer:

10√3+10

Explanation:

20cos30+20sin30

20(√3/2)+20(1/2)

10√3+10

Answer 2

Answer:

Explanation:

To find the Y component of the resultant we need to add F1y and F2y

F1y=F1sintheta

=20sin(30)

=10

F2y=F2sintheta

=20sin(60)

=10$\sqrt{3}$

Fy= F1Y + F2y

Fy=10+10$\sqrt{3$

Fy=27.3 N