Question

Two forces of magnitude 50 N and 40 N each are applied on

a block in opposite direction. What will be the net force on that block?
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Answer 1

Answer:

the net force is 10 N on the direction of the person who applied 50 N force

Answer 2

Aɴꜱᴡᴇʀ

There will be a force of 10 N on the direction of the 50 N force

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Gɪᴠᴇɴ

☞ Two forces of 50 N is applied on a direction d and a force of 40 N is on its opposite direction and let it be is -d

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ᴛᴏ ꜰɪɴᴅ

➠ The net force

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Sᴛᴇᴘꜱ

➜$\sf{}as \: given \: that \: they \: both \: act \: on \: opposite \: direction \\ \\ \huge\sf{ \orange{f_{net} = \: sum \: of \: the \: forces }}$

★ As are given that the forces are in opposite directions then let us take one force 50 N and the other as -40 N

So,

$\leadsto \tt{}f_{net} = 50 + ( - 40) \\ \\ \leadsto \tt{}f_{net} = 50 - 40 \\ \\ \tt {\dashrightarrow{}f_{net} = \large \purple{ 10 \: N}}$

For easy understanding:-

✪ We could also assume the force 50 N as negative and 40 N as positive but the force will be in negative( in the direction of the 50 N force) but we did the opposite way just for simplicity.

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