Two forces of magnitude F and √3 F act at right angles to each other. Their resultant makes an angle β with F. The value of β is
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Explanation:
let the resultant be equal to R.
R=√F^2 +3F^2
R=√4F^2
R=2F.
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Given:
The magnitude of 1st force, F1 = F
The magnitude of 2nd force, F2 = √3 F
The angle between the two forces, θ = 90°
To Find:
The angle β made by the resultant with force F1.
Calculation:
- To calculate the angle, we have:
tan β = (F2 sin θ) / (F1 + F2 cos θ)
⇒ β = tan⁻¹ (√3 F sin 90°) / (F + √3 F cos 90°)
⇒ β = tan⁻¹ (√3 F / F)
⇒ β = tan⁻¹ (√3)
⇒ β = tan⁻¹ ( tan 60°)
⇒ β = 60°
- So the angle made by resultant with F is 60°.
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