Two forces p and q are applied as a point a of a hook support. Knowing that p=75n and q=125n, determine the magnitude and direction of their resultant
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Answer ⇒ 200 N in the same direction of p and q.
Explanation ⇒
p = 75 N, q = 125 N.
Angle between the 2 vectors is not given in Question, but it is given both force are applied at same point, thus we can consider that they are in same direction.
Thus, angle = 0.
Hence,
|R|² = |p|² + |q|² + 2|p|q|Cos0
∴ |R|² = 75² + 125² + 2 × 75 × 125
∴ |R|² = 5625 + 15625 + 18750
∴ |R|² = 40000
∴ |R| = 200 N.
Hence, the resultant magnitude is 200 N.
Direction of Resultant,
tan(τ) = pSinθ/(q + pcosθ)
∴ tan(τ) = 0
(τ) = 0
Hence, direction of resultant is same as that of p and q.
Hope it helps.
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