Two forces P and Q are in ratio P:Q=1: 2.IF
magnitude of their resultant is √8P and angle
between P and Q is X then value of cos (X) is.
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Answer:
Step-by-step explanation:
Answer Text
tan−1(12)
45∘
30∘
60∘
Answer :
A
Solution :
tanα=QsinθP+Qcosθ
3–√2=sinθPQ+cosθ⇒3–√2=sinθ(1/2)+cosθ⇒34=(2sinθ1+2cosθ)2
⇒3(1+2cosθ)2=16sin2θ
⇒3(1+4cos2θ+4cosθ)=16(1−cos2θ)
⇒3+12cos2θ+12cosθ=16−16cos2θ
⇒28cos2θ+12cosθ−13=0⇒ cosθ=(1)/(2),−0.92
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