two forces whose magnitude are at the ratio of 3:5 give a resultant of 35N .If the angle of inclination is 60 .find magnitude of each force
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16
Let a be constant in forces.
That is 3a : 5a
Applying the formula,
35² = (3a)² + (5a)² + 2(3a)(5a)cos60°
1225 = 34a² + 15a²
1225 = 49a²
1225/49 = a²
[35/7]² = a²
5² = a²
5 = a
So forces are 3a = 15 N
and 5a = 25 N
Thank you too much.
That is 3a : 5a
Applying the formula,
35² = (3a)² + (5a)² + 2(3a)(5a)cos60°
1225 = 34a² + 15a²
1225 = 49a²
1225/49 = a²
[35/7]² = a²
5² = a²
5 = a
So forces are 3a = 15 N
and 5a = 25 N
Thank you too much.
assingh:
Thank you
Answered by
1
Answer is 25 N
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