Physics, asked by semsoyang19839612455, 1 day ago

Two forces X = 50N and Y = 60 N are acting on a wooden block and it moves to the left as shown below in figure.​

Answers

Answered by kaushikpoojari06
1

Answer:

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Answered by hotelcalifornia
0

Given:

Force acting towards left = Y = 60 N

Force acting towards right = X = 50 N

To Find: Nature and magnitude of Net Force

Calculation:

  • When more than one force acts on an object, the net force is the addition of all individual forces considering the direction all these forces.
  • Let direction towards left be positive sign,

Fnet = Y + (-X) = 60 - 50 = 10 N

  • So, the sign of net force is positive i.e. towards left direction and magnitude is 10 N.
  • Since net force is not non zero, it is unbalanced force.

Answer:

Nature of net force is unbalanced force and magnitude is 10 N in left direction.

Your question is incomplete. You might be referring to the complete question below:

"Two forces X = 50N and Y = 60 N are acting on a wooden block and it moves to the left as shown below in figure.​ What is the nature and magnitude of net force?"

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