Question

Two forceses of 4 Nutron and 6 Newton
lact on a body of Mass 2

kg perpen-
decularly find resulten acceleration
acting
a body
on​

Answer 1

Answer:

Two forceses of 4 Nutron and 6 Newton

lact on a body of Mass 2

kg perpen-

decularly find resulten acceleration

acting

a body

on​

Explanation:

Answer 2

Magnitude of Resultant:

Since F

1

and F

2

are perpendicular

∴ Magnitude of Resultant force on body is given by

R=

F

1

2

+F

2

2

=

8

2

+6

2

N =10N

Direction of Resultant:

θ =tan

−1

F

1

F

2

[Refer Fig. 2]

=tan

−1

8

6

=36.9

o

≈37

o

Step 3: Applying Newton’s second Law for finding acceleration [Refer Fig. 3]

F

net

=ma

⇒ 10=5a

⇒ ∣

a

∣=2m/s

2

Hence magnitudes of acceleration is 2m/s

2

directed at 37

o

from the 8 N force.