Question

Two four-sided dice are rolled. What is the probability that the sum of the numbers showing is greater than three?

Answer 1

Here, it is given that two four sided dice are rolled.

Sample space :

(1,1) , (1,2) , (1,3) , (1,4) , (2,1) , (2,2) , (2,3) , (2,4) , (3,1) , (3,2) , (3,3) , (3,4) , (4,1) , (4,2) , (4,3) , (4,4)

Total outcomes = 16

Favourable outcomes :

(1,3) , (1,4) , (2,2) , (2,3) , (2,4) , (3,1) , (3,2) , (3,3) , (3,4) , (4,1) , (4,2) , (4,3) , (4,4)

So, favourable outcomes = 13

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As we know that :

Probability = Favourable outcomes/Total outcomes

Now,

We'll find the probability of sum of the numbers which are greater than 3.

=> Probability = Favourable outcomes/Total outcomes

=> Probability = 13/16

Hence, the final answer is 13/16

Therefore, the probability of sum of the numbers which are greater than 3.