Accountancy, asked by Goutami606, 1 year ago

Two friend p and q started a business investing the amount in the ratio of 5:6 joined them after six month. investing an amount of equal that of q's amount at the end of the year 20%of profit was earn whuch is equal to 98000 what was the amount invested by r

Answers

Answered by flower161
6
Answer: Rs.210000
Explanation:
Let the total profit be Rs. z.
Then, 20% of z = 98000
<=> z= 98000*100/20 = 490000.
Let the capitals of P, Q and R be Rs. 5x, Rs. 6x and Rs. 6x respectively.
Then, (5x * 12) + (6x * 12) + (6x * 6) = 490000 * 12
<=> 168x = 490000 * 12
<=> x = 490000*12/168 = 35000.
R's investment = 6x = Rs.(6 * 35000) = Rs. 210000.(Answer)
Answered by ya17kun
0

Answer:

Consider initial investments of P,Q,R as 5x,6x,6x respectively

(5x*12)+(6x*12)+(6x*6)=98,000

5x+6x+3x=98,000 ---- (1)

we get

x=7000

frm (1) we can see that the ratio of profits of P,Q,R is 5:6:3

thus profits of R is 3x=21,000

Profit% on R= (20%)*(6/12)=10%

Thus 10% of x=21,000

So x=2,10,000

PS: Its a tricky sum thats not easily understood ... I tried my best to explain it in simple words hope it helps

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