Two friends a and b each having mass 40 kg are playing with a ball of mass 5kg, on a frictionaless surface a throws the ball towards b with speed of 4m/s. Then the speed of a and b after b catches the ball fir the first time are
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Explanation:
In the case 1 Total momentum of the man A and the ball will remain constant
Therefore ,
0 = 4 x 5 - 40 x v
Velocity will be = 0.5 m/s towards left .
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