Question

Two friends a and b each having mass 40 kg are playing with a ball of mass 5kg, on a frictionaless surface a throws the ball towards b with speed of 4m/s. Then the speed of a and b after b catches the ball fir the first time are

Answer 1

Explanation:

In the case 1 Total momentum of the man A and the ball will remain constant

Therefore ,

0 = 4 x 5 - 40 x v

Velocity will be = 0.5 m/s towards left .