Two friends A and B start a race, and together they run for 50 mts. Then A turns right and runs
28 mts while B turns left and runs 20 mts. Then A turns right and runs 10 mts. B also turns right and
runs 10 mts. How far are the two friends now from each other ?
(1) 50 mts (2) 52 mts (3) 60 mts (4) 49 mts
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By calculations the answer is 52m.
Here we took out the displacement from E to G (the final position of B and A)by using the Pythagorean theorem. 1st we considered the distance from E to C as the hypotenuse of triangle EDC and calculated it's length (Pythagorean theorem) equal to 22.3. Similarly in triangle GCF, GC is the hypotenuse and it's length is 29.7(Pythagorean theorem). Next we added the distance of EC and CG as EC + CG = EG (the displacement)
=> 22.3+29.7=52.
Here we took out the displacement from E to G (the final position of B and A)by using the Pythagorean theorem. 1st we considered the distance from E to C as the hypotenuse of triangle EDC and calculated it's length (Pythagorean theorem) equal to 22.3. Similarly in triangle GCF, GC is the hypotenuse and it's length is 29.7(Pythagorean theorem). Next we added the distance of EC and CG as EC + CG = EG (the displacement)
=> 22.3+29.7=52.
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ramveerkumar30:
explain with diagram
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