Two friends Ajay and Bharath start a business together. They decided toshare their capitals depending upon the variable expenditure.The capital of the two partners together is given by the polynomial 6x2 +11x-35 ,which is the product of their individual share factors. On the basis of the above information answer the following questions
1) The total expenditure of Ajay and Bharath when x=10 (in rupees) (a)375 (b) 475 (c) 575 (d) 675
2) The shares of Ajay and Bharath individually is (a)2x+7 ,3x-5 (b) 3x-5 ,2x+7 (c) both (a) and (b) (d) none of the above
3) The value of x, when their shares are equal 12 (b) 10 (c) 8 (d) 6
4) The value of x, when their total share is equal to 0 -7/2 (b) 5/3 (c) both (a) and (b) (d) none of the above
5) The sum of their expenditure is 5x-2 (b) 5x+2 (c) 4x-2 (d) 4x+2
Answers
Answer:
ANSWER IS IS THE CORRECT ANSWER
Step-by-step explanation:
I THINK IT IS THE CORRECT ANSWER HOPES IT HELPS YOU
Given:
Total share of Ajay and Bharat is represented by 6x²+11x-35,
To Find:
1) The total expenditure of Ajay and Bharat when x=10
2) The shares of Ajay and Bharat individually is
3) The value of x, when their shares are equal
4) The value of x, when their total share is equal to 0
5) The sum of their expenditure is 5x-2
Explanation:
1. Expenditure is given by 6x²+11x-35, at x= 10
6×10²+11×10-35
=600+110-35
Expenditure =675 Rs
2. 6x²+11x-35
6x²-10x+21x-35
2x(3x-5) +7(3x-5)
(2x+7)(3x-5)
The shares of Ajay and Bharat individually are (2x+7) and(3x-5)
3. when shares are equal means
(2x+7) = (3x-5)
x=12, shares are equal
4. total share is equal to0, means
The expenditure, 6x²+11x-35=0
(2x+7)(3x-5)=0
x= -7/2 and 5/3 both
5. sum of their shares are (2x+7) + (3x-5)
sum of their shares =5x-2