Two friends appear in a interview for two vacancies in the same post. The probability of first friend's selection is 1/5 and that of second friend is 1/6 . What is the probability that none of them will be selected.
Answers
Answered by
1
Answer:
19/30
Step-by-step explanation:
first friend= 1/5 chance
second friend=1/6 chance
both getting it= 1/5 + 1/6
= 6/30+5/30
=11/30
None getting it= 30/30-11/30
= 19/30
If there are any errors please notify me
Answered by
1
Answer:
frist friends =1/5 change. second friends =1/6 change. both getting it =1/5+1/6=6/30+5 /30 =11/30 none getting it30/30-11/30=19/30 if there are any errors please notify me.
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