Two friends are assigned to complete a job, where one friend can complete the job in half the time of other friend, so in how many days will they will complete the job, working together, if the slower one completes the job in 12 days ?
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Answer:
4 days
Step-by-step explanation:
s is slower, f is faster
total work = time × efficiency = 1×12 =12
no. of days taken by f
= total work/ efficiency of f
= 12/2 =6 days
efficiency of S+F = 1+2 =3
no. of days taken by s+f = 12/3 =4 days
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