Math, asked by aaryajha33, 1 year ago

Two friends are at a distance of 72km . They start at the same time to meet each other and walk at the rates of 7 km and 5 km per hour respectively. In what time will they meet?

Answers

Answered by nsopagu
2
They covered the distance in this way together in different hours.
6+6.5+7+7.5+8+8.5+9+9.5+10 = 72 Means,they'll meet at the 9thhr.
So,In that time A will cover = 4*9 = 36km. 
They will meet in Midway.

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Answered by nirajgautam
3

Answer:

distance=72km

Step-by-step explanation:

let speed of 1st friend be 7km/h,And 2nd friends be 5km/h...

A/Q

In 1 hour 1st friend cover 7km

in 1st hour 2nd friend cover 5km

similarly,

In 6th hours 1st friend cover= (7.6)km=42km

In 6th hours 2nd friends cover=(5.6)=30km

Therefore

Both cover(42+30) in 6th hours.

so, they will meet in 6 hours.

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