Question

Two friends are racing. The first friend is running around the rectangular pull with the length of 50 m and the second friend is swimming along the length of the pool.the first friend is running three times faster than the second friend is swimming. When the first friend runs 5 times around the pool second friends swims 6 lengths of the pool. Find the width of the pool

Answer 1

Solution :-

Let us assume that, width of the pool is B m .

given that,

• first friend speed : second friend speed = 3 : 1 .

Also,

• Time taken to cover distance around 5 times by first friend = Time taken to cover along length 6 times.

we know that,

• Perimeter of rectangle = 2(L + B)
• Time = Distance / speed .

A/q,

→ {5*2(L + B)/3} = (6 * L) / 1

→ 10(50 + B) /3 = (6 * 50)

→ 10(50 + B) = 900

→ 50 + B = 90

→ B = 90 - 50

→ B = 40 m (Ans.)

Hence, The width of the pool is 40 m.

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Answer 2

Answer:

Width of pool is 50m.

Step-by-step explanation:

Given: Length of pool=50 m , first friend is running three times faster than the second friend is swimming & also time taken by first friend to complete 5 rounds is same as time taken by second to swim 6 lengths of the pool.

To find: width of the pool.

Let width of the pool is x m.

By given condition:

Ratio of speed of first friend to second friend's speed = 3 : 1 .

Also, time taken to cover distance around 5 times by first friend = Time taken to cover along length 6 times.

We know that,

Perimeter of rectangle = 2(L + B)

Time = Distance / speed .

According to question:

{5*2(L + B)/3} = (6 * L) / 1

10(50 + x) /3 = (6 * 50)

10(50 + x) = 900

50 + x = 90

x= 90 - 50

x = 40 m

Hence, the pool is of width 40 m.

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