Math, asked by 97priyarohini, 1 year ago

Two friends bought two bags whose prices were in the ratio of 1:3. If they sold them at a loss of 10%, the difference of the money earned by them was rs.360. What was the cost price of the cheaper bag?

Answers

Answered by Shaizakincsem
7

Thank you for asking this question. Here is your answer:

Let the ratio of the cheaper bag be x the costly bag will be 3x.


Their selling prices will be :


0.9x for the cheaper one.


3x × 0.9 = 2.7x


The differences of what is earned on the bags on selling is :


2.7x - 0.9x = 360


1.8x = 360


x = 360/1.8


x = 200


The cost price of the costlier one is :


3 × 200 = 600


Rs 600

If there is any confusion please leave a comment below.

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