Question

Two friends, one on a bike and the other in a car, arrive together at a parking lot. The chance that the one in the car will find a parking space is 0.1, and the one on the bike not finding a parking space is 0.1. What is the probability that only one of them finds a parking space?

Answer 1

DeaR STudENT HERe IS UR AnS:

LeT A n B as Event of Friend on bike and Friend on 2 car to Get a parking space.

So Given

p(A') = 0.1 => p (A) = 0.9

p(B) = 0.1 => p ( B')= 0.1

Probality of that only one would get the parking space

= p( A n B') + p(A ' n B)

Since, A nd B are independent fuent so.,

p(A n B) = p(A) * p(B)

Required Ans = p (A n B) + p (A' n B)

= p (A) . p(B) + p ( A') . p(B)

= 0.9 * 0.1 + 0.1 * 0.9

= 0.09 + 0.09

= 0.18

STudY WeLL...

Answer 2

Answer:

0.82 is the correct answer