Question

Two friends, Pari and Brenda, go to a fair. There is a fixed entry fee. They both have fascination for clay dolls. Price of all the clay dolls is the same. Pari and Brenda buy 9 and 13 clay dolls respectively. Pari spent Rs. 66 and Brenda Rs. 86 in all. Calculate the entry fee and the price of each doll.

Answer 1

GiveN :

• Two friends Pari and Brenda go to fare.
• The entry ticket was same.
• They buy clay dolls
• Pari spent 86 Rs.
• Brenda spent 86 Rs.

To FinD :

• Price of each doll
• fee entry

SolutioN :

Pari and Brenda go to a fare, they buy clay dolls and spent on entry tickets. Pari spent Rs. 66 and Brenda Spent Rs. 86

A.T.Q,

Let the price of dolls be x and price of entry ticket be y

So, for Pari

⇒ 9x + y = 66 .....(1)

For Brenda,

⇒13x + y = 86 ......(2)

__________________________

(2) - (1)

13x + y = 86

9x + y = 66

(-) (-) (-)

__________

4x = 20

__________

⇒ 4x = 20

⇒x = 20/4

⇒x = 5

$\therefore$ Price of each clay doll is Rs. 5

_____________________________

put value of x in (1)

⇒9(5) + y = 66

⇒45 + y = 66

⇒y = 66 - 45

⇒y = 21

$\therefore$ Entry fee is Rs. 21

Answer 2

${\bf{\boxed{\bf{\red{Answer:}}}}}$

Given question:

⇏ Two friends, Pari and Brenda, go to a fair. There is a fixed entry fee. They both have fascination for clay dolls. Price of all the clay dolls is the same. Pari and Brenda buy 9 and 13 clay dolls respectively. Pari spent Rs. 66 and Brenda Rs. 86 in all.

To Find:

⇏ Calculate the entry fee and the price of each doll.

According to the question:

⇏ Let us assume x and y as the suitable variables.

Calculations:

⇏ $\sf (9x + y) = 66 --- Equation-(1)$

⇏ $\sf (13x + y) = 86 --- Equation-(2)$

Subtracting equation (2) with (1), we get:

⇏ $\sf (13x + y) = 86$

⇏ $\sf (9x + y) = 66$

⇏ ${\bf{\boxed{\bf{4x = 20}}}}$

Putting the values from above equation:

⇏ $\sf 4x = 20$

⇏ $\sf x = \dfrac{20}{4}$

⇏ ${\bf{\boxed{\bf{x = 5}}}}$

Therefore, 5 rupees is the price of each clay doll.

Putting the values for x in equation (1):

⇏ $\sf (9 \times 5) + y = 66$

⇏ $\sf (45 + y) = 66$

⇏ $\sf y = (66 - 45)$

⇏ ${\bf{\boxed{\bf{y = 21}}}}$

Therefore, rupees 21 is the entry fee.