Question

two friends paul and peter are invited to attend a conference. the probability of paul and peter going to the conference is 0.25 and 0.5 respectively. if the probability of both of them going together is 0.15, then what is the probability that neither of them go to the conference?

Answer 1

P(of paul going) = 0.25

P(of Peter going) = 0.5

P(both going together) = 0.15

P(Paul not going) = 0.75

P(Peter not going) = 0.5

P(them not going together) = 0.85

P(neither of them goes) = P(Paul does not go) and P(Peter does not go) and P(they are not going together)

This equals to :

0.75 × 0.5 × 0.85 = 0.31875