Two friends S and A takes a straight route to the same terminal point and travel with constants speeds. At the initial moment, the positions of the two and the terminal point form an equaliteral triangle. When a covered distance of 80km, the new positions of S and A and terminal points form a right angled triangle. When A was at a distance of 120km from the terminal point, S arrived at the terminal point. Find the initial distance between them
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Answer:
υ
2
−u
2
=2a×180
⇒45
2
−u
2
=360a
υ=u+at⇒45=u+a×6
Solve to get u=15ms
−1
, a=5ms
−2
u
2
=0
2
+2ax⇒15
2
=0
2
+2×5x⇒x=22.5m
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