Two friends Seema and Aditya work in the same office at Delhi. In the Christmas
vacations, both decided to go to their hometowns represented by Town A and Town B
respectively in the figure given below. Town A and Town B are connected by trains
from the same station C (in the given figure)in Delhi.Based on the given situation,
answer the following questions: and what is formula
Answers
on Christmas vacations, Aditya Travels more Distance than Seema . Mid point is (5/2 , 9/2) & Area = 17 sq units
Step-by-step explanation:
C = (-4 , 4)
Seema goes to Town A (1 , 7)
Distance Seema Travels = √{(1 - (-4))² + (7 - 4)²}
= √(25 + 9)
= √34
Aditya goes to Town B (4 , 2)
Distance Aditya Travels = √{(4 - (-4))² + (2 - 4)²}
= √(64 + 4)
= √68
= √2 * √34
√68 > √34
=> Aditya Travels more Distance
A (1 , 7) , B (4 , 2)
D mid point of A & B
= (1 + 4)/2 , (7 + 2)/2
D = 5/2 , 9/2
A (1 , 7) , B (4 , 2) ,C (-4 , 4)
Area of Δ ABC
= (1/2) | 1(2 - 4) + 4 (4 - 7) -4(7 - 2)|
= (1/2) | -2 -12 - 20|
= (1/2) | -34|
= 34/2
= 17
Area of ΔABC = 17 Sq units.
Learn more:
Two friends Seema and Aditya work in the same office at Delhi. In ...
brainly.in/question/13273885
Two friends Seema and Aditya work in the same office at Delhi. In ...
brainly.in/question/13107676
Who will travel more distance, Seema or Aditya, to reach to their ...
brainly.in/question/13273826
