Question

Two friends started from same point with same constant acceleration of 5m/s2

Second one starts

journey 5s later. Find the time taken by 1st one such that he is 100m ahead of second one. ​

Answer 1

Answer:

If the time travelled upto the given point by second one is tseconds, the first one has taken t +5seconds.

Since the difference between their distances travelled is 100m,

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