Physics, asked by chinnupoojya, 6 months ago

two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one

Answers

Answered by kubetkumar60

Answered by sudiptadandapat001

Answer:

So the time taken by the 1 st one is 8.5 sec..

Hope it will be helpfull

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two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one​

Answers

So the time taken by the 1 st one is 8.5 sec..

two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one