Question

two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one​

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Two friends started from same point...

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Two friends started from same point with same constant acceleration of 5m/s2 second one starts journey 5 s later. Find the time taken by 1st one such that he is 100 Fullscreen

Two friends started from same point with same constant acceleration of 5m/s2 second one starts journey 5 s later. Find the time taken by 1st one such that he is 100m ahead of second one.

JEE/Engineering Exams

Physics

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Two friends started from same point with same constant acceleration of 5m/s2 second one starts journey 5 s later. Find the time taken by 1st one such that he is 100m ahead of second one. Fullscreen

Accelevatian of both =5m/s2

Nihal velocity, u = 0 m/s

Let the gaop of 100m be achieved after t seconds 1st one

start running

∴S=ur+12at2∴S=12×5×t2

∴ The dist. travelled by 2nd one =12×5×(t−5)2

A/Q

52t2−52(t−5)2=100

a1+z2−[t2+25−10t]=40

→10t−25=40

a,10t=65

∴t=6.5s