Question

two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one​

answer is 8.5 seconds how..??​

Answer 1

Answer:

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Explanation:

If the time travelled upto the given point by second one is tseconds, the first one has taken t +5seconds.

Since the difference between their distances travelled is 100m

Answer 2

Explanation:

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