Physics, asked by swetha99089, 7 months ago

two friends started from same point with some constant acceleration of 5m/s second one starts journey 5 sec later. find the time taken by 1 St one such that he is 100m ahead of 2 nd one
answer is 8.5 seconds how..??

Answers

Answered by ECHAYAN

5

Answer:

i think the option is wrong or may be i am wrong anyway the answer i got is in the attachment....always stay curious

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