Two full turns of the circular scale of a screw gauge cover a distance of 1mm on its main scale and
has total 50 divisions. Further, it was found that it has negative error of -0.03 mm. While measuring the
diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale
divisions in line the main scale as 35. Find the diameter of the wire
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Answer:
least count of screw gauge =0.5/50mm=0.01mm
:-reading =[main scale reading + circular scale reading *L.C] -(zero error)
=[3+35*0.01] - (0.03)
3.38mm answer
Explanation:
nice question
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