Question

two full turns of the circular scale of a screw gauge cover a distance of 1mm on its main Scale. the total number of the division in the circular scale is 50 . further it is found that the screw gauge has a zero error of-0.03 mm. while measuring the diameter of a thin wire a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. then the diameter of the wire..​

Answer 1

Step-by-step explanation:

(a) : Least count of the screw gauge = (0.5mm)/50 = 0.01mm

Main scale reading = 3mm.

Vernier scale reading = 35

Therefore, Observed reading = 3 + 0.35 = 3.35

zero error = –0.03

Therefore, actual diameter of the wire = 3.35 – (–0.03) = 3.38mm.

Answer 2

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(a) : Least count of the screw gauge =

(0.5mm)/50 = 0.01mm

• Main scale reading = 3mm.

• Vernier scale reading = 35

Therefore, Observed reading = 3 + 0.35 = 3.35

zero error = –0.03

Therefore, actual diameter of the wire = 3.35 – (–0.03) = 3.38mm.

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