Two gas bulbs are connected by a this tube. calculate the partial pressure of He after the conne valve is opened at a constant temperature of 27°C ? Не 0.63 atm 1.2 L Ne 3.4L 2.8 atm a) 1 atm b) 0.328 atm c) 1.64 atm d) 0.166 atm
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Explanation:
n
He
=
RT
PV
=
0.0821×300
0.63×1.2
=0.03
n
Ne
=
0.0821×300
2.8×3.4
=0.39
x
He
=
n
He
+n
Ne
n
He
=
0.03+0.39
0.03
=0.0714
Total pressure after connecting the bulbs will be:
P
1
V
2
+P
2
V
2
=P
R
(V
1
+V
2
)
0.63×1.2+2.8×3.4=P
R
(1.2+3.4)
P
R
=2.33 atm
P
He
=x
He
×P
R
=0.0714×2.33=0.166 atm
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